Textbooks say that for a distant external observer, an infalling object never reaches the horizon because dr/dtdr/dt tends to 0 as rr approaches 2M2M . But this conclusion assumes the object is a test particle with negligible mass. If we take the object's own mass mm seriously, then the exterior spacetime is determined by the total mass M+mM+m . The new horizon is at 2(M+m)2(M+m) , so the old surface 2M2M is no longer the true coordinate singularity. That means the object's radial velocity does NOT vanish at 2M2M ; it only vanishes asymptotically at the new horizon 2(M+m)2(M+m) . So the coordinate time needed for the object to cross the original 2M2M surface is finite. My question: Does this show that the "eternal freezing" result is only valid for test particles, and that a finite massive object can indeed enter the original horizon within finite external time? Am I missing something?