What is a number whose Lagrange number is Freiman's constant? – mathoverflow.net
John C. Baez
For any irrational $x \in \mathbb{R}$ we define its Lagrange number to be the supremum of real numbers $c$ such that
$$ \displaystyle{ \left| \frac{p}{q} - x \right| < \frac{1}{cq^2} }$$
has ...
