A seemingly easy kinematics problem

The question states "Given the relation of position w.r.t. time, find the time at which velocity is zero." The relation is: $x = \sqrt{t} + 2$ First, I tried differentiating with respect to $t$ , which led to this: \begin{align*} \frac{dx}{dt} &= \frac{d}{dt}\left(\sqrt{t}+2\right) \\[1ex] v &= \frac{1}{2\sqrt{t}} \end{align*} Now obviously for $v=0$ , either the numerator needs to be $0$ , or the denominator needs to approach infinity. However both of these are not the answer. Then i tried to graph this function and got asymptotes both as $t$ approaches infinity and at $t=0$ . Are there any real possible solutions here? I was handed this out by my teacher so i am pretty sure an answer should be possible that too one which is not too hard to find, but i have been scratching my head on this for over a hour.