Hot Questions - Stack Exchange28d agoWhat is wrong in my Taylor series approximation? – math.stackexchange.comRajaKrishnappaI have a time dependent function as follows: f(x+δ(t))=cos(2π⋅(x−δ(t))+0.05sin(60π(x−δ(t)))f(x + \delta (t)) = \cos(2\pi \cdot (x - \delta(t)) + 0.05\sin(60\pi(x - \delta(t)))f(x+δ(t))=cos(2π⋅(x−δ(t))+0.05sin(60π(x−δ(t))) where δ(t)=0.05t\delta(t) = 0.05tδ(t)=0.05t and f(x,t=0)=f(x) f(x,t=0) = f(x)f(x,t=0)=f(x). Using the Taylor ...Read at Hot Questions - Stack ExchangeTagscalculusmathematicsnumerical-methods
