Recall that the harmonic series n=11n\displaystyle{\sum_{n=1}^{\infty}\frac{1}{n}} diverges. This is because we may bound the partial sums below, like so: 1+12+(13+14)+(15+16+17+18)+>1+\frac{1}{2}+\left(\frac{1}{3}+\frac{1}{4}\right)+\left(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}\right)+\cdots > 12+12+(14+14)+(18+18+18+18)+=\frac{1}{2}+\frac{1}{2}+\left(\frac{1}{4}+\frac{1}{4}\right)+\left(\frac{1}{8}+\frac{1}{8}+\frac{1}{8}+\frac{1}{8}\right)+\cdots= 12+12+12+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\cdots\to\infty We may replace nn by an+ban+b, whe